Question:
The weight of earth?
fdgfdgd
2006-03-25 22:10:29 UTC
I would like to know how to figure out an approximate weight of earth.

PLEASE DONT GIVE ME THE ANSWER, IWOULD LIEK TO FIND IT ON MY OWN.
Nine answers:
2006-03-25 22:16:53 UTC
Well, not only did the kittykid give you an answer, he didn't give you the right answer, and wasn't just wrong in the way allamerican noted.



There's a difference between mass and weight. Weight is the effect of gravity on mass.



All matter has mass. But what something weighs depends on the gravitational pull placed on that mass.



Astronauts weigh less on the Moon than they do on Earth, because the Moon itself has less mass than Earth, and thus exerts less gravitational pull on them.



Weight is also regulated by the proximity of objects to one another; the closer you are to another mass, the more force it exerts on you, and thus the more you weigh in relation to it.



Therefore, how much the Earth weighs depends on from what other object in space you want to measure its weight. On the sun, the Earth would weigh much more than it does on Pluto.
Thermo
2006-03-25 22:32:07 UTC
Moon revolves Earth in (almost) a circle.

It needs centripetal force Fc =mv2/r.

It is delivered by gravity Fg = GMm/d2

d=r. Make the next equation: Fc=Fg.

Moon's mass dissapers from the equation.

Solve the mass of the Earth and find M = 6 x 10^24 kg.

This method can be used for any planet with at least one sattelite.
2006-03-25 22:12:29 UTC
The mass of the Earth may be determined using Newton's law of gravitation. It is given as the force (F), which is equal to the Gravitational constant multiplied by the mass of the planet and the mass of the object, divided by the square of the radius of the planet. We set this equal to the fundamental equation, force (F) equals mass (m) multiplied by acceleration (a). We know that the acceleration due to gravity is equal to 9.8 m/s2, the Gravitational constant (G) is 6.673 x 10-11 Nm2/kg2, the radius of the Earth is 6.37 x 106 m, and mass cancels out. When we rearrange the equation and plug all the numbers in, we find that the mass of the Earth is 5.96 x 1024 kg.



F = Gm1m2/r2 = ma



Gm/r2 = g



m = gr2/G



m = (9.8 m/s2)(6.37 x 106 m)2/(6.673 x 10-11 Nm2/kg2)



m = 5.96 x 1024 kg



The Earth gains mass each day, as a result of incoming debris from space. This occurs in the forms of "falling stars", or meteors, on a dark night. The actual amount of added material depends on each study, though it is estimated that 10 to the 8th power kilograms of in-falling matter accumulates every day. The seemingly large amount, however, is insignificant to the Earth's total mass. The Earth adds an estimated one quadrillionth of one percent to its weight each day.
2016-05-20 09:29:45 UTC
The surface gravity of a planet is proportional to the mass of the planet and the distance you are from the centre. The mass of the moon is less than the mass of the Earth (the moon is only 0.012 the mass of the Earth). And the distance from the centre of the moon to its surface is also less than Earth (the radius of the moon is only 0.27 that of Earth). So when you do the math, the surface gravity on the moon is one sixth that of Earth.
averageamerican001
2006-03-25 22:14:35 UTC
Mr. SmartyPants above was sort of correct, except his statement that the earth only gains mass at night is inaccurate. The earth gains mass day and night, constantly.



Also, the universe is expanding, is as all matter, at an equal rate thereby increasing the mass of the earth, and all portions thereof and thereout.
Pearlsawme
2006-03-25 22:24:16 UTC
Weight or Mass. If you refer the force with which earth is pulled towars Sun, then the force F is given by



F = G M m / r^2.



G = 6.673* 10^(-11) N m^2 kg^(-2)

M = 1.99 * 10^30 kg.-mass of Sun.

m = 5.977* 10^24 kg.-mass of Earth.

r = 1.496* 10^11 m. -Distance of Earth from Sun
doodlee2k
2006-03-25 22:31:10 UTC
Excuse me but isn't weight a force, and as such the earth's net force at its centre would be zero since opposing segments of its sphere would cancel out. To a person on the surface its weight would be the the reaction he feels,ie. his or her weight. You would be crushed otherwise.
leblongeezer
2006-03-25 22:20:17 UTC
Just the case this is a trick question, the weight of Earth is zero.
abuji94
2006-03-25 22:48:11 UTC
then find it.


This content was originally posted on Y! Answers, a Q&A website that shut down in 2021.
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